[解決済み】C++ シンプルなハングマンゲーム【終了しました

質問

こんにちは、私は3日前にc++を始め、いくつかのチュートリアルなどを読みました。私は、初心者にとって簡単な作業に思えたので、自分自身のハングマンゲームを作りたかったのですが、私は問題につまずきました。1文字の文字列をアンダースコアと入れ替え、アンダースコアが足りない単語に変わるようにする方法が見つからない以外は、すべてうまくいっています。そのため、基本的にはコンパイル時に単語全体を推測することができます。

以下はそのコードです。

#include <iostream>
#include <string>
using namespace std;
string player1,player2,word,underscore,guess;
int wrong=0;
int main (){
string copy = word;


cout << "----------------------Hello! Welcome to the HANGMAN game!----------  ----------" << endl;
cout << "Please type in your name, PLAYER 1" << endl;
cin >> player1;
cout << "Please type in your name, PLAYER 2" << endl;
cin >> player2;
cout << "OK " << player1 << " and " << player2 << ". Let's start with the    game!" << endl;
cout << player1 << " please input the word you want " << player2 << " to guess." << endl;

cin >> word;

//space
for (int x=0; x<30; x++){
cout << endl;
}

//UNDERSCORE
while (underscore.size() != word.size()){
underscore.push_back('_');}

cout << underscore << endl;

//MAIN WHILE
while(wrong<12){
cin >> guess;

//IF GUESS ISNT LETTER
if(guess.size() > 1){
if(guess==word){
cout << "Thats the right word." << endl;
break;
}
else{
cout << underscore << endl;
cout << "Wrong word try again." << endl;
cout << "Used: " << usedguess << endl;
wrong ++;
}

    }





if(underscore == word){
  cout << "You win!" << endl;
  break;
}



if(wrong==1){
cout << "I" << endl;
}
else if(wrong==2){
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==3){
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==4){
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==5){
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==6){
cout << "I===" << endl;
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==7){
cout << "I===" << endl;
cout << "I  O" << endl;
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==8){
cout << "I===" << endl;
cout << "I  O" << endl;
cout << "I  |" << endl;
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==9){
cout << "I===" << endl;
cout << "I  O" << endl;
cout << "I -|" << endl;
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==10){
cout << "I===" << endl;
cout << "I  O" << endl;
cout << "I -|-" << endl;
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==11){
cout << "I===" << endl;
cout << "I  O" << endl;
cout << "I -|-" << endl;
cout << "I /"  << endl;
cout << "I" << endl;
}
else if(wrong==12){
cout << "I===" << endl;
cout << "I  O" << endl;
cout << "I -|-" << endl;
cout << "I / /"<< endl;
cout << "I YOU ARE DEAD" << endl;

cout << "Game over bro! The word was: " << word <<endl;
break;
}
}
}

解決方法は？

の文字列を比較するために word と guess の場合、for ループで文字列を繰り返し、一致するかどうかを確認することができます。

string word  = "hangman";
string guess = "mansomething";
string underscore = string(word.size(), '_'); // init a string with underscores equal to the length of 'word'

// iterate over the characters in word and guess
for (size_t i = 0, iend = min(word.size(), guess.size()); i < iend; i++) {
    if (word[i] == guess[i])
        underscore[i] = word[i];  // if the characters match at position i, update the underscore.
}

cout << underscore << endl;

その後 underscore は以下を含む。

_an____